Hallo, guten morgen Gast!
0,5x^3-1,5*(a+1)*x^2+6at-120 = 0,5x^3-1,5*(b+1)*x^2+6bt-120
-1,5*(a+1)*x^2+6at = -1,5*(b+1)*x^2+6bt [ / 1,5
-(a+1)*x^2+4at = -(b+1)*x^2+4bt
(b + 1 - a - 1) * x² = 4t * (b - a)
(b - a) * x² = (b - a) * 4t
x² = 4t
x = 2 √ (t)
Gruß asinus :- )
!
!
