Two cyclists, 40 miles apart, start riding toward each other at the same time. One cycles 3 times as fastas the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Distance = Rate • Time 40 mi = (R + 3R)(2 hr)
20 mi/hr = 4R
slower bike = R R = 5 mi/hr
faster bike = 3R 3R = 15 mi/hr
check answer
5 mi/hr • 2 hr = 10 miles slow cyclist went this far
15 mi/hr • 2 hr = 30 miles fast cyclist went this far
total distance = 40 miles
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