A right circular cone of base radius 1 and slant height 3 is given. P is a point on the circumference of the base. Find the length of the shortest path from P around the cone and back to P.
The base circumference is 2 π r = 6.28 so that's the distance from P all the way around the cone.
This problem is so easy, I kept looking for the catch, for what I'm missing, but I can't find anything.
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In isosceles triangle ABC, angle A is 40 degrees. Find all possible values of angle B.
If A (40o) is the apex angle, then B and C are (1/2)(180o – 40o) = 70o
If B is the apex angle, then A (40o) and C are 40o and B is 180o – 80o = 100o
If C is the apex angle, then A (40o) and B are the equal base angles, and they = 40o
A teacher has made ten statements for a True-False test.
Four statements are true and six are false.
How many distinct answer keys could the
The four (true) answers can be arranged 10C4 = 210 ways.
The six (false) answers can be arranged 10C6 = 210 ways.
For each way the true answers can be arranged,
the false answers can be arrangeddd 210 ways.
So there could be 210 x 210 = 44,100 answer keys.
If a, b, c, are positive integers such that abc = 210, find the minimum value of a + b + c.
I think it's 18
The factors of 210 are 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70, 105 and 210.
check answer
5 x 6 x 7 = 210
5 + 6 + 7 = 18
My assignment says that 980*2+4000*2+350*12+2500*12 =43980
But that ain't true. The answer should be 44160
There's 180 in difference. I don't get it!
I get the same answer that you did, i.e., 44160.
Maybe somebody copied something incorrectly.
a tiger eats a lamm in 3 hours a lion eats a lamm in 6 hours a bird eats a lamm in 10 hours if they eat together how long does it take?
1/3 lamm/hr is tiger's rate
1/6 lamm/hr is lion's rate
1/10 lamm/hr is bird's rate
add rates 1/3 + 1/6 + 1/10 is the rate for all together
1 1 1
–– + –– + ––
3 6 10
10 5 3 18
–– + –– + –– = –– lamm / hr
30 30 30 30
invert rate 30
–– hr / lamm reduces to 1 2/3 hour per lamm
18
So, it takes the three of them together 1 hour and 40 minutes to eat a lamm
A vertical pole AB measuring 5 meters snaps at point C. The pole remains in contact at C and the top of the pole touches the ground at point T, a distance of 3 meters from A. Find the length AC, in meters, the point where the pole snapped.
CT2 = AC2 + AT2
CT2 = (5 – CT)2 + 32
CT2 = 25 – 10CT + CT2 + 9
10CT = 34
CT = 3.4
AC = 5 – 3.4
AC = 1.6
60 numbers have an average of 24. Two numbers are discarded, and the average of the remaining 58 numbers is 25. Find the sum of the two discarded numbers.
60 • 24 = 1440
58 • 25 = 1450
–10
if y = 0.32x - 20.51, what would y be if x=175
y = ( 0.32 • x ) – 20.51
y = ( 0.32 • 175 ) – 20.51
y = 61.25 – 20.51
y = 40.74
what is multiply -180 and add is -8
10 & –18
10 x –18 = –180
10 + –18 = –8
how long would it take us to go to pluto if the space craft was traveling at 93,000 km/h
5,900,000,000 km
––––––––––––––– = 63,441 hr
93,000 km/hr
63,441 hr converts to 7 years and 3 months
The distance varies according to where the planets are in their respective orbits,
but the average distance from Earth to Pluto is approximately 5.9 billion kilometers.
x + 1
y = –––––––––––
x2 – 2x + 1
(x – 1)(x – 1)
The asymptote is when the denominator equals zero
So the asymptote is when x = 1
A jar contains two red marbles, three green marbles, ten white marbles and no other marbles. Two marbles are randomly drawn from this jar without replacement. What is the probability that these two marbles drawn will both be red?
red marbles in jar = 2
all marbles in jar = 15
chance of 1st drawn marble being red = 2 / 15
red marbles in jar = 1
all marbles in jar = 14
chance of 2nd drawn marble being red = 1 / 14
chance of both things happening = (2 / 15) • (1 / 14) = 2 / 210
reduces to = 1 / 105
