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heureka

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 #2
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how do I solve 2/(sqrt(4sqrt(2)+6))+2/(sqrt(6-4*sqrt(2)) , without calculator, it's been an hour at least..

 

26+42+2642=2(16+42+1642)=2(642+6+426+42642)=2(642+6+42(6+42)(642))=2(642+6+4236162)=2(642+6+424)=2(642+6+422)=642+6+42

26+42+2642=642+6+42|()2=(642+6+42)2=(642)+26426+42+(6+42)=6+26426+42+6=12+26426+42=12+2(642)(6+42)=12+236162=12+24=12+22=12+4=1626+42+2642=4

 

laugh

21.04.2016
 #3
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remainder of 2^2011/13

 

22011(mod13)= ?

 

1.gcd(13,2)=1|13 and 2 are relatively prim 2.13 is a prim number 3.ϕ() is Euler's totient function, Euler's phi function ϕ(p)=p1p is a prim numberϕ(13)=124.2ϕ(13)1(mod13)2121(mod13) Let ϕ(n) denote the totient function. Then aϕ(n)1(modn) for all a relatively prime to n.

 

5.2011=12167+722011(mod13)=212167+7(mod13)=(212)16727(mod13)(1)16727(mod13)127(mod13)27(mod13)128(mod13)11(mod13)

 

The remainder of 2201113 is 11

 

laugh

11.04.2016