mit \(\sqrt{x} = x^\frac{1}{2}\) und Potenzregel:
\(\frac{d}{dx} \sqrt{x} = \frac{d}{dx} x^{\frac{1}{2}} = \frac{1}{2} * x^{(\frac{1}{2}-1)} = \frac{1}{2} * x^{(-\frac{1}{2})} = \frac{1}{2} * \frac{1}{x^{(\frac{1}{2})}} = \frac{1}{2} * \frac{1}{\sqrt{x} } \)
