+0

# Wieso gibt 6+9^3+6589*2-9/6*log(90+1)= 16 ????

0
567
2

Wieso gibt 6+9^3+6589*2-9/6*log(90+1)= 16 ????

27.06.2015

### Beste Antwort

#2
+14538
+3

$${\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{9}}}^{{\mathtt{3}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6\,589}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{6}}}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{90}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right) = {\mathtt{13\,910.061\: \!437\: \!911\: \!518\: \!359\: \!6}}$$

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27.06.2015

#1
0

Das ist großer Quatsch, was Du da aufgeschrieben hast.

27.06.2015
#2
+14538
+3
Beste Antwort

$${\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{9}}}^{{\mathtt{3}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6\,589}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,-\,}}{\frac{{\mathtt{9}}}{{\mathtt{6}}}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{90}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right) = {\mathtt{13\,910.061\: \!437\: \!911\: \!518\: \!359\: \!6}}$$