(4*v+4*s)/(3*m-3*j)/(4*v+4*s)/(m-j)
Wenn es einer Schafft bitte mit Lösungsweg :-D Ich blick nicht durch :D
(4*v+4*s)/(3*m-3*j)/(4*v+4*s)/(m-j)
\(\frac{(4*v+4*s)}{(3*m-3*j)}\div (4*v+4*s)\quad /(m-j)\\ =\frac{(4*v+4*s)}{(3*m-3*j)(4*v+4*s)}\div \quad (m-j)\\ =\frac{(4*v+4*s)}{(3*m-3*j)(4*v+4*s) (m-j)}\\ =\frac{4(v+s)}{3(m-j)*4(v+s) (m-j)}\\ =\frac{1}{3(m-j) (m-j)}\\ =\frac{1}{3m^2-6mj+3j^2}\\ \)
(4*v+4*s)/(3*m-3*j)/(4*v+4*s)/(m-j)
Wenn es einer Schafft bitte mit Lösungsweg :-D Ich blick nicht durch :D
Hi Omi,
You have answered this question
[ (4*v+4*s)/(3*m-3*j) ] / [ (4*v+4*s)/(m-j) ]
But there are no brackets in the question so , the division must be done from left to right like I have done it.
Perhaps the question asker intended your question - I do no know what was in her/his head.