wie geht das?

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3xy((y²/3x²)-(5y/2x²)+(3/x))=?

Guest 12.01.2017

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Beste Antwort

3xy((y²/3x²)-(5y/2x²)+(3/x))=?

Omi67 12.01.2017

Omi67 · Answer 1 · 2017-01-12T03:33:28

3xy((y²/3x²)-(5y/2x²)+(3/x))=?

asinus · Answer 2 · 2017-01-12T05:59:45

3xy((y²/3x²)-(5y/2x²)+(3/x))=?

$\large 3xy((\frac{y^2}{3x^2} )-(\frac{5y}{2x^2} )+(\frac{3}{x} ))$

$\large =\frac{3xy(2y^2-15y+8x)}{6x^2}$

$\large=\frac{6xy^3-45xy^2+24x^2y}{6x^2}$ \3x

$\large=\frac{2y^3-15y^2+8xy}{2x}$

$\large=\frac{y}{2x}\times(2y^2-15y+8x)$

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