Wenn man die Klammer auflösen will, stimmt dieses Rechnung ( Resultat ) 10- (2a+2b):2= 10-2a- 2b Weil vor der Klammer ein Minus steht, werden nach der Division, die Zeichen umgewandelt
$${\mathtt{10}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right){\mathtt{\,\times\,}}{\mathtt{2}}}{{\mathtt{2}}}} = {\mathtt{10}}{\mathtt{\,-\,}}\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right) = {\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}$$
$${\mathtt{10}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right){\mathtt{\,\times\,}}{\mathtt{2}}}{{\mathtt{2}}}} = {\mathtt{10}}{\mathtt{\,-\,}}\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right) = {\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}$$