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Wenn man die Klammer auflösen will, stimmt dieses Rechnung ( Resultat ) 10- (2a+2b):2= 10-2a- 2b Weil vor der Klammer ein Minus steht, werden nach der Division, die Zeichen umgewandelt

 27.07.2015

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 #1
avatar+14537 
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10 - (2a+2b) : 2 = 10 - ( 2a/2 +2b/2 ) = 10 - (a + b ) = 10-a-b

oder so ;

$${\mathtt{10}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right){\mathtt{\,\times\,}}{\mathtt{2}}}{{\mathtt{2}}}} = {\mathtt{10}}{\mathtt{\,-\,}}\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right) = {\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}$$

 

Gruß radix !

 27.07.2015
 #1
avatar+14537 
+3
Beste Antwort

10 - (2a+2b) : 2 = 10 - ( 2a/2 +2b/2 ) = 10 - (a + b ) = 10-a-b

oder so ;

$${\mathtt{10}}{\mathtt{\,-\,}}{\frac{\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right){\mathtt{\,\times\,}}{\mathtt{2}}}{{\mathtt{2}}}} = {\mathtt{10}}{\mathtt{\,-\,}}\left({\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{b}}\right) = {\mathtt{10}}{\mathtt{\,-\,}}{\mathtt{a}}{\mathtt{\,-\,}}{\mathtt{b}}$$

 

Gruß radix !

radix 27.07.2015

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