Welches Kapital bringt bei einem Zinssatz von 6% in sechs Tagen genau 6 € Zinsen
+14538 $${\mathtt{Z}} = {\frac{{\mathtt{K}}{\mathtt{\,\times\,}}{\mathtt{t}}{\mathtt{\,\times\,}}{\mathtt{p}}}{\left({\mathtt{360}}{\mathtt{\,\times\,}}{\mathtt{100}}\right)}}$$ => $${\mathtt{K}} = {\frac{\left({\mathtt{Z}}{\mathtt{\,\times\,}}{\mathtt{360}}{\mathtt{\,\times\,}}{\mathtt{100}}\right)}{\left({\mathtt{t}}{\mathtt{\,\times\,}}{\mathtt{p}}\right)}}$$
$${\frac{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{360}}{\mathtt{\,\times\,}}{\mathtt{100}}\right)}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{6}}\right)}} = {\mathtt{6\,000}}$$
!+14538 $${\mathtt{Z}} = {\frac{{\mathtt{K}}{\mathtt{\,\times\,}}{\mathtt{t}}{\mathtt{\,\times\,}}{\mathtt{p}}}{\left({\mathtt{360}}{\mathtt{\,\times\,}}{\mathtt{100}}\right)}}$$ => $${\mathtt{K}} = {\frac{\left({\mathtt{Z}}{\mathtt{\,\times\,}}{\mathtt{360}}{\mathtt{\,\times\,}}{\mathtt{100}}\right)}{\left({\mathtt{t}}{\mathtt{\,\times\,}}{\mathtt{p}}\right)}}$$
$${\frac{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{360}}{\mathtt{\,\times\,}}{\mathtt{100}}\right)}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{6}}\right)}} = {\mathtt{6\,000}}$$
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