Wie kann ich folgendes unter Verwendung der Potenzgesetze vereinfachen ? :
x^5*y^5*(xy)^-4
Bitte mit Lösungsweg. Nicht schlimm, wenn nicht vorhanden.
Dankeschön
+14538 $${{\mathtt{x}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{\left({\mathtt{x}}{\mathtt{\,\times\,}}{\mathtt{y}}\right)}^{\left(-{\mathtt{4}}\right)} = {\frac{{{\mathtt{x}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{5}}}}{\left({{\mathtt{x}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{4}}}\right)}} = {\mathtt{x}}{\mathtt{\,\times\,}}{\mathtt{y}}$$
!+14538 $${{\mathtt{x}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{\left({\mathtt{x}}{\mathtt{\,\times\,}}{\mathtt{y}}\right)}^{\left(-{\mathtt{4}}\right)} = {\frac{{{\mathtt{x}}}^{{\mathtt{5}}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{5}}}}{\left({{\mathtt{x}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{y}}}^{{\mathtt{4}}}\right)}} = {\mathtt{x}}{\mathtt{\,\times\,}}{\mathtt{y}}$$
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