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0,3(b-c)^5 *1,8(b-c)^8

Guest 19.01.2023

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Vereinfache!

Hallo Gast!

$0,3(b-c)^5 \cdot 1,8(b-c)^8\\ =0,3\cdot 1,8\cdot (b-c)^5\cdot (b-c)^8\\ =\color{blue}0,54\cdot (b-c)^{13}=\dfrac{27\cdot (b-c)^{13}}{50}$

!

asinus 21.01.2023

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