ax^-4:(ax)^-4= ?
Was ist das Ergebnis?
Ich hab da a^-4*x raus, aber das ist doch nicht richtig, oder?
Danke für eure Hilfe, die bisher gegeben habt und auch weiter geben werdet :)
+14538 $${\frac{{\mathtt{a}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{\left(-{\mathtt{4}}\right)}}{{\left({\mathtt{a}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}^{\left(-{\mathtt{4}}\right)}}}$$ = $${\mathtt{a}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{\left(-{\mathtt{4}}\right)}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{4}}} = {{\mathtt{a}}}^{{\mathtt{5}}}$$
!+14538 $${\frac{{\mathtt{a}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{\left(-{\mathtt{4}}\right)}}{{\left({\mathtt{a}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}^{\left(-{\mathtt{4}}\right)}}}$$ = $${\mathtt{a}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{\left(-{\mathtt{4}}\right)}{\mathtt{\,\times\,}}{{\mathtt{a}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{4}}} = {{\mathtt{a}}}^{{\mathtt{5}}}$$
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