+15000 Nullstelle finden:
\(\color{BrickRed}f(x) = 2\cdot lg(x^2 - 2x) + 3=0\\ lg(x^2-2x)=-1,5\\ x^2-2x=10^{-1,5}\\ x^2-2x-0,03162=0 \)
\(x=1\pm\sqrt{1+10^{-1,5}}\\ x=1\pm 1,0157\)
\(\color{blue}x_1=2,0157\\ x_2=-0,0157\ \small{entfaellt,\ lg\ ist\ komplex}\)
\(\mathbb L=\{2,0157\}\)
Probe: \(2\cdot lg(2,0157^2-2\cdot 2,0157)+3\approx 0\)
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