1/6*x+2/3*x+1/3*x+1/9+1/9*x
Hallo Gast!
\(\frac{1}{6}x+\frac{2}{3}x+\frac{1}{3}x+\frac{1}{9}+\frac{1}{9}x=\frac{(3+12+6+2)x}{18}+\frac{1}{9}\color{blue}=\frac{23}{18}x+\frac{1}{9}\)
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