Integral

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[0 −(1/3 x^3 )]+[(1/3 2^3−2^2 )−0]+[(1/3 3^3−3^2 )−(1/3 2^3−2^2 )]

Guest 13.12.2021

bearbeitet von asinus 13.12.2021
bearbeitet von asinus 13.12.2021

asinus · Answer 1 · 2021-12-13T11:22:19

Hallo Gast!

$\int([0 −(1/3 x^3 )]+[(1/3 2^3−2^2 )−0]+[(1/3 3^3−3^2 )−(1/3 2^3−2^2 )])dx \\ =\color{blue}- \dfrac{x^4}{12}-8,99997217353x+C$

!