in klammern???

in klammern???

-20t²+23bt-6b²

${\color{red}-20\ t²+23b\ \cdot t-6b² }=0=(-20)\cdot(t-t_1)\cdot (t-t_2)$

.   a           b                c

$t = {-b \pm \sqrt{b^2-4ac} \over 2a}$

$t = {-23b \pm \sqrt{23^2\cdot b^2-4\cdot ( -20) \cdot (-6b^2)} \over -40}$  

$t=\frac{-23\pm \sqrt{529b^2-480b^2}}{-40}$

$t=\frac{-23b\pm \sqrt{49b^2}}{-40}$

$t=\frac{-23b\pm 7b}{-40}$

$t_1=\frac{2}{5}b$   

$t_2=\frac{3}{4}b$

$-20\ t²+23b\ \cdot t-6b²=(-20)\cdot(t-\frac{2}{5}b)\cdot (t- \frac{3}{4}b)$ 

  !