+15080 in klammern???
-20t²+23bt-6b²
\({\color{red}-20\ t²+23b\ \cdot t-6b² }=0=(-20)\cdot(t-t_1)\cdot (t-t_2)\)
. a b c
\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(t = {-23b \pm \sqrt{23^2\cdot b^2-4\cdot ( -20) \cdot (-6b^2)} \over -40}\)
\(t=\frac{-23\pm \sqrt{529b^2-480b^2}}{-40}\)
\(t=\frac{-23b\pm \sqrt{49b^2}}{-40}\)
\(t=\frac{-23b\pm 7b}{-40}\)
\(t_1=\frac{2}{5}b\)
\(t_2=\frac{3}{4}b\)
\(-20\ t²+23b\ \cdot t-6b²=(-20)\cdot(t-\frac{2}{5}b)\cdot (t- \frac{3}{4}b)\)
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