Hilfe was ist 6x+(3-x)*2+11=27 war ergiebt X ? bzw wie geht das

6x+(3-x)*2+11 = 27
6x+6-2x+11     = 27
4x+17              = 27   |-17
4x                    = 10   |/4
x                      = 2,5

Radix hat hierbei einen kleinen Fehler gemacht. Er hat (3-x)^2 statt (3-x)*2 gerechnet.

Hier die Lösung der Gleichung

6x + (3-x)² + 11 = 27             Klammer mit 2. Binom aflösen

6x + 9 -6x + x² + 11 =  27             Zusammenfassen und ordnen

                x² + 20    = 27

                          x²  = 7             x1 = + sqrt(7)         x2 = - sqrt(7)

$${{\mathtt{x}}}^{{\mathtt{2}}} = {\mathtt{7}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{7}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
{\mathtt{x}} = {\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
\end{array} \right\}$$

Ich hoffe, dir geholfen zu haben!   

Gruß "radix" $$\mathrm{\ }$$

$${\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{x}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{11}} = {\mathtt{27}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{7}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
{\mathtt{x}} = {\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
\end{array} \right\}$$