Hilfe was ist 6x+(3-x)*2+11=27 war ergiebt X ? bzw wie geht das ? ich blicke gerade überhaupt nicht durch ? Danke im Vorraus!
Hier die Lösung der Gleichung
$${{\mathtt{x}}}^{{\mathtt{2}}} = {\mathtt{7}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{7}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
{\mathtt{x}} = {\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
\end{array} \right\}$$
$${\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{x}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{11}} = {\mathtt{27}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{7}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
{\mathtt{x}} = {\mathtt{2.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
\end{array} \right\}$$