Guten Abend !
1) 3=log2(x/6)
3=log[(x)−log(6)log(2)
log(x)=3∗log(2)+log(6)
x=48 Probe: log2(48/6) = 3
Gruß radix !
Aufgabe 2 :
log(x):log(6)=log(x):log(2)+1
x=2−log(6)log(3)
x=0,32288
x=2−1,63092975357...
Guten Morgen Gast! Guten Morgen radix!
Ist das nicht so gemeint?
1) 3=log2(x/6)
3 = log2(x/6)
2³ = x/6
x = 2³ * 6
x = 48
2) log6(x)=ln(x)+1
log6(x) = ln(x) + 1
6lnx+1= x
ln6*(lnx + 1) = lnx
ln6 * lnx + ln6 = lnx
ln6 * lnx - lnx = - ln6
lnx * (ln6 -1) = - ln6
lnx = - ln6 / (ln6 -1)
x = e- ln6 / (ln6 -1)
x = e-2,2630098393
x = 0,104036878753
Gruß asinus :- )
!