1/3=1-e^-k*15 wie bekomme ich -k ?
\({\color{red}\frac {1}{3}=1-e^{-15k}} \)
\(e^{-15k}=1-\frac{1}{3} \)
\(-15\times k=ln\frac{2}{3} \)
\({\color{blue}-k = \frac {ln\frac {2}{3}}{15}}\) = - 0,0270310072072
asinus :- ) !
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