+265 Hi,
ich brauche hilfe.
$${\mathtt{\,-\,}}{\frac{{\mathtt{25}}}{{\mathtt{15}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{2}}}{{\mathtt{10}}}}$$=
$${\frac{{\mathtt{3}}}{{\mathtt{7}}}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)$$=
$${\frac{{\mathtt{7}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{8}}}}\right){\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{3}}}}$$=
DANKE im vorraus
+14538 1.) = $${\mathtt{\,-\,}}{\frac{{\mathtt{50}}}{{\mathtt{30}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{6}}}{{\mathtt{30}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{44}}}{{\mathtt{30}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{22}}}{{\mathtt{15}}}}$$
2.) = $${\frac{{\mathtt{6}}}{{\mathtt{14}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{7}}}{{\mathtt{14}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{14}}}}$$
3.) = $${\frac{{\mathtt{84}}}{{\mathtt{24}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{6}}}{{\mathtt{24}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{8}}}{{\mathtt{24}}}} = {\frac{{\mathtt{98}}}{{\mathtt{24}}}} = {\frac{{\mathtt{49}}}{{\mathtt{12}}}}$$
!
+265 Hi,
kannst du mir Vielleicht sagen was bei dieser Aufgabe raus kommt:
[3,5*(15:60+12:60)]*(-$${\frac{{\mathtt{20}}}{{\mathtt{21}}}}$$)
Bitte mit Rechenweg
Gruß Sprotte22
+14538 $${\mathtt{\,-\,}}{\frac{{\mathtt{14\,405}}}{{\mathtt{6}}}} = -{\mathtt{2\,400.833\: \!333\: \!333\: \!333\: \!333\: \!3}}$$
!
+12531 Hallo Sprotte22
radix hat die Aufgabe falsch abgeschrieben.
Gruß
und Dank an radix. Immer diese Flüchtigkeitsfehler
+14538
! ( und noch einmal DANKE für den Hinweis !)
!
