+0  
 
0
376
1
avatar

die Wurzel.

\(\sqrt{\large 10x^{\frac{1}{3}}\cdot \sqrt[3]{\frac{1}{x}}-y^\frac{1}{2}\cdot \sqrt{y}} \)

 15.06.2021
 #1
avatar+3976 
0

\(\sqrt{\large 10x^{\frac{1}{3}}\cdot \sqrt[3]{\frac{1}{x}}-y^\frac{1}{2}\cdot \sqrt{y}} = \sqrt{\large 10x^{\frac{1}{3}}\cdot (\frac{1}{x^\frac{1}{3}})-y} = \sqrt{10-y}\)

.
 16.06.2021

2 Benutzer online

avatar