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(-3)×1/3×16×2^3×(-3)×(-1/4^2)×(-2)×-1)

Kompletter Rechenweg bitte

 25.02.2015

Beste Antwort 

 #1
avatar+14538 
+5

(-)*(-)*(-)*(-)*(-)    =>   (-)    Das Ergebnis wird also negativ !

 

$${\frac{{\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{{\mathtt{4}}}^{{\mathtt{2}}}}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{1}}$$      nun kann gekürzt werden

 $${{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{2}}$$      =    $${{\mathtt{2}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{\mathtt{3}} = {\mathtt{48}}$$       =>  - 48   (siehe oben!)

 

Gruß radix !      $${\frac{\left(-{\mathtt{3}}\right){\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}\left(-{\mathtt{3}}\right){\mathtt{\,\times\,}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{{\mathtt{4}}}^{{\mathtt{2}}}}}\right){\mathtt{\,\times\,}}\left(-{\mathtt{2}}\right){\mathtt{\,\times\,}}\left(-{\mathtt{1}}\right) = -{\mathtt{48}}$$

 25.02.2015
 #1
avatar+14538 
+5
Beste Antwort

(-)*(-)*(-)*(-)*(-)    =>   (-)    Das Ergebnis wird also negativ !

 

$${\frac{{\frac{{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{{\mathtt{4}}}^{{\mathtt{2}}}}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{1}}$$      nun kann gekürzt werden

 $${{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{2}}$$      =    $${{\mathtt{2}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{\mathtt{3}} = {\mathtt{48}}$$       =>  - 48   (siehe oben!)

 

Gruß radix !      $${\frac{\left(-{\mathtt{3}}\right){\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}\left(-{\mathtt{3}}\right){\mathtt{\,\times\,}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{{\mathtt{4}}}^{{\mathtt{2}}}}}\right){\mathtt{\,\times\,}}\left(-{\mathtt{2}}\right){\mathtt{\,\times\,}}\left(-{\mathtt{1}}\right) = -{\mathtt{48}}$$

radix 25.02.2015
 #2
avatar+14538 
0

Gruß radix !

 25.02.2015

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