Allgemeine Rechenfrage

Wie rechnet man (2-17/16)x(-12)-15x-3/20

${\color{red}(2-\frac{17}{16} )\times (-12)-15\times (-\frac{3}{20} )}$

= ${\color{Black}\frac{(32-17)\times (-12)}{16}+\frac{45}{20} }$

= $-\frac{180}{16}+\frac{9}{4}$ =  $\frac {-180+36}{16}$

= $-\frac{144}{16}$

= ${\color{Blue}-9}$      !