((3^x+1)/5)*(2^x)=12

Guten Abend Anonymous,

$${\frac{\left(\left({{\mathtt{3}}}^{{\mathtt{x}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right){\mathtt{\,\times\,}}{{\mathtt{2}}}^{{\mathtt{x}}}\right)}{{\mathtt{5}}}} = {\mathtt{12}}$$

$${{\mathtt{6}}}^{{\mathtt{x}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{2}}}^{{\mathtt{x}}} = {\mathtt{60}}$$                  

x = 2,2393506896...

Probe:    $${{\mathtt{6}}}^{{\mathtt{2.239\: \!35}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{2}}}^{{\mathtt{2.239\: \!35}}} = {\mathtt{59.999\: \!929\: \!439\: \!945\: \!282\: \!4}}$$

Gruß radix !   ( und eine gute Nacht ! )

(3^(x+1)∙2^x)/5=12

oder

((3^x+1)∙2^x)/5=12