2^x= 8^1/4

8 = 2³

$${{\mathtt{2}}}^{{\mathtt{x}}} = {\left({{\mathtt{2}}}^{{\mathtt{3}}}\right)}^{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)}$$       =>      $${{\mathtt{2}}}^{{\mathtt{x}}} = {{\mathtt{2}}}^{\left({\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)}$$         =>        x = $${\frac{{\mathtt{3}}}{{\mathtt{4}}}}$$