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[(+2 3/4)*(-1 1/11)]/(+1 1/5)

 24.11.2015

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[(+2 3/4)*(-1 1/11)]/(+1 1/5)

 

\(\begin{array}{rcl} \dfrac{ \left( +2 \frac34 \right) \cdot \left( -1 \frac{1}{11} \right) } { +1 \frac15 } &=& \dfrac{ \left( \frac{ 2\cdot 4+3 }{4} \right) \cdot \left( - \frac{ 1\cdot 11+1 }{11} \right) } { \frac{ 1\cdot 5+1 }{5} } \\ &=& \dfrac{ \left( \frac{11}{4} \right) \cdot \left( - \frac{12}{11} \right) } { \frac{6}{5} } \\ &=& -\dfrac{ \left( \frac{11}{4} \right) \cdot \left(\frac{12}{11} \right) } { \frac{6}{5} } \\ &=& -\dfrac{ \left( \frac{12}{4} \right) \cdot \left(\frac{11}{11} \right) } { \frac{6}{5} } \\ &=& -\dfrac{ 3 }{ \frac{6}{5} } \\ &=& - \frac{3 \cdot 5}{6} \\ &=& - \frac52 \\ &=& - 2\frac12 \\ &=& - 2,5 \\ \end{array}\)

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 25.11.2015
 #1
avatar+26367 
+5
Beste Antwort

[(+2 3/4)*(-1 1/11)]/(+1 1/5)

 

\(\begin{array}{rcl} \dfrac{ \left( +2 \frac34 \right) \cdot \left( -1 \frac{1}{11} \right) } { +1 \frac15 } &=& \dfrac{ \left( \frac{ 2\cdot 4+3 }{4} \right) \cdot \left( - \frac{ 1\cdot 11+1 }{11} \right) } { \frac{ 1\cdot 5+1 }{5} } \\ &=& \dfrac{ \left( \frac{11}{4} \right) \cdot \left( - \frac{12}{11} \right) } { \frac{6}{5} } \\ &=& -\dfrac{ \left( \frac{11}{4} \right) \cdot \left(\frac{12}{11} \right) } { \frac{6}{5} } \\ &=& -\dfrac{ \left( \frac{12}{4} \right) \cdot \left(\frac{11}{11} \right) } { \frac{6}{5} } \\ &=& -\dfrac{ 3 }{ \frac{6}{5} } \\ &=& - \frac{3 \cdot 5}{6} \\ &=& - \frac52 \\ &=& - 2\frac12 \\ &=& - 2,5 \\ \end{array}\)

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heureka 25.11.2015

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