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1500 ml zu 11 % plus 700 ml zu 40 % ergeben 2200 ml zu ? %

 06.11.2014

Beste Antwort 

 #1
avatar+14538 
+5

Hallo Anonymous,

1500 ml  mit  11 %  ( Alkohol)   =>   165 ml   (Alkohol)

  700 ml  mit  40 %          "         =>   280 ml         "

2200 ml                                     =>     445 ml        " 

 100  ml                               =>  20,23 ml    "  

                                            =>   445*100/2200 = 20,23   %

$${\frac{{\mathtt{445}}{\mathtt{\,\times\,}}{\mathtt{100}}}{{\mathtt{2\,200}}}} = {\frac{{\mathtt{445}}}{{\mathtt{22}}}} = {\mathtt{20.227\: \!272\: \!727\: \!272\: \!727\: \!3}}$$

Du hast also 2200 ml  mit 20,23 % ( Alkohol ).

Gruß radix !  ( Prost ! )

 06.11.2014
 #1
avatar+14538 
+5
Beste Antwort

Hallo Anonymous,

1500 ml  mit  11 %  ( Alkohol)   =>   165 ml   (Alkohol)

  700 ml  mit  40 %          "         =>   280 ml         "

2200 ml                                     =>     445 ml        " 

 100  ml                               =>  20,23 ml    "  

                                            =>   445*100/2200 = 20,23   %

$${\frac{{\mathtt{445}}{\mathtt{\,\times\,}}{\mathtt{100}}}{{\mathtt{2\,200}}}} = {\frac{{\mathtt{445}}}{{\mathtt{22}}}} = {\mathtt{20.227\: \!272\: \!727\: \!272\: \!727\: \!3}}$$

Du hast also 2200 ml  mit 20,23 % ( Alkohol ).

Gruß radix !  ( Prost ! )

radix 06.11.2014

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