120x + x^2 = 66.6cm^2

Hi,

das  cm² hinter der  66,6  wollen wir mal vergessen!

x^2+120x-66,6=0      und nun die  p-q-Formel !

x1/2 = -60 +- $${\sqrt{{{\mathtt{60}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{66.6}}}}$$

x1/2 = -60 +- 60,5525       =>     x1 = -120,5525       ;     x2 = 0,552457

$${\sqrt{{{\mathtt{60}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{66.6}}}} = {\mathtt{60.552\: \!456\: \!597\: \!565\: \!057}}$$

Gruß radix !