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Hallo

Habe eine Mathe HÜ

 

0=1-2b-a-b/2a

b=?

danke

 24.02.2015

Beste Antwort 

 #3
avatar+12530 
+9

.
 24.02.2015
 #1
avatar+14538 
+5

1-2b-a-b/2a=0             Gleichung  * 2a

2a-4ab-2a²-b=0

-4ab-b = 2a²-2a

4ab+b = 2a-2a²

b*(4a+1) = 2a*(1-a)

$${\mathtt{b}} = {\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{a}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{a}}\right)\right)}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{a}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}}$$             b = 2a*(1-a) / (4a+1)

 

Gruß radix !

 24.02.2015
 #2
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$${\mathtt{0}} = {\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,-\,}}{\mathtt{a}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{b}}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{a}}\right)}}\right)$$

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{b}}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{a}}\right)}}\right) = {\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{a}}$$

$${\mathtt{b}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{a}}\right)}}\right) = {\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{a}}$$

$${\mathtt{b}} = {\frac{\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{a}}\right)}{\left({\mathtt{2}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{1}}}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{a}}\right)}}\right)\right)}}$$

gruß

gandalf the green

 24.02.2015
 #3
avatar+12530 
+9
Beste Antwort

Omi67 24.02.2015

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