Straight

Hello Guest,

it's me again, Straight, The answer is 9996. In the Orange party there are 11424 votes and then "which was seven eightshs of the Blue party vote that means \(\frac{7}{8}\) \( {of\ the\ Orange\ party}={Blue\ party}\). You know there are 11424 votes for the Orange party so: \(\frac{7}{8}\)\(*\ 11424\ votes\) and that's 9996 votes.

So I think my answer is correct.

Straight

Hello Guest,

(correction: Celia got 80% in her first three exams.)

Her reasoning is wrong because it would be right if she has written

one exam, this would be \(\frac{80+94}{2}\), which is 87%, but there are three

exams and not just one. So it equals: \(\frac{80+80+80+94}{4}\), which is 83.5%.

So her overall mark is no 87%, but it is 83.5%. It applies:

\(\frac{Sum\ of\ values }{Number\ of\ values}\) and that is the overall mark formula.

Straight

hello Guest,

the result is -12.

Steps:

\(-2*6\)

\(-12\)

Straight

Yes, that's right,

and when the question is "What is the smallest three-digit multiple of 9 whose digits' sum is 18", it would be 189, I guess.

Straight

Hello Guest,

no, think again about what you are saying.

You will get the answer.

Straight

Hello,

m and n can only be bigger than 4125 or 2816000,

\(m=15\) \(\frac{15!}{4125}=317011968\) and

 \(n=15\) \(\frac{15!}{2816000}=464373\) .

n is also 15.

Straight

It's \(2*(9+7)\) and that equals \(2*16\) and that is 32.

Hope this was hopeful.

Straight

My thinking:

1)  

  (a)   (i) 9996 (\(11424*\frac{7}{8}\))

         (ii) It is then a consequential error, if you have (i) wrong,

              then you would also have (ii) wrong.

              21420 (\(11424+9996\))

  (b)   (i) rounded to 50.61% (\(\frac{42320}{100}\)) is 423.2 and (\(\frac{21420}{423\frac{1}{5}}\))

  From here I have to go.

Straight

Ooh, 15 questions and 1 answer (not really an answer because this wasn't helpful to anyone).

For helping people, you can ask questions, but you didn't do it.

Straight