Straight

4 balloons = 0.25 of a smile

8 balloons = 0.5 of a smile

a * b * c = -2660/27

Man kann von der Gleichung $(4a + a) \cdot 3 = 60$ auch distributieren.

$(4a + a) \cdot 3 = 60 \mbox{ }| \mbox{ } distributieren \\ (4a \cdot 3) + 3 \cdot a = 60 \\ 12a + 3a = 60 \\ 15a = 60 \mbox{ }| :15 \\ a = 4$

So erhält man trotzdem das gleiche Ergebnis.

(Edit: LaTeX-Probleme..)

Also theoretisch $(4a + a) \cdot 3 = 60$.

$(4a + a) \cdot 3 = 60 \mbox{ }| : 3 \\ (4a + a) = 20 \\ 5a = 20 \mbox{ }| : 5 \\ a = 4$

Der 1. Summand ist größer als der 2. Summand. Der 1. Summand ist 4a und a = 4, also sind dann 4a = 16, und der 2. Summand 4.

wait wait wait, why do have a different answer...?

*0**

The first digit can be 5, 6, 7           3 values

The second digit must be 0           1 value

The third digit can be 0-9             10 values

The fourth digit can be 0-9           10 values

3 * 1 * 10 * 10 = 300.

8000 is also a possible value.       +1

300 + 1 = 301 values.

uhm

500_               10 values (0 - 10)

510_               10 values (0 - 10)

520_               10 values (0 - 10)

530_               10 values (0 - 10)

540_               10 values (0 - 10)

550_               10 values (0 - 10)

560_               10 values (0 - 10)

570_               10 values (0 - 10)

580_               10 values (0 - 10)

590_               10 values (0 - 10)

                       ---------------

                        10 * 10 = 100 values.

so when the first digit is 6 or 7, then there are (100 * 3 =) 300 values + 8000 works. So there are (300 + 1 =) 301 values.

$5000 \leq n \leq 8000$ (representation to LaTeX) ...

The product of the digits is always 0 if it contains at least one 0. n is a 4-digit positive integer that cannot have a 0 at the beginning.

0*** -> 0 ways
*0** -> 301 ways
**0* -> 301 ways
***0 -> 301 ways

so 0 + 301 + 301 + 301 = 903 ways. (the calculation path is from Melody)

information: It applies 0! = 1 .

So you're actually solving $\sqrt{y} = \sqrt{x^2} = 9$ .

Ignore $\sqrt{x^2}$, then the equation would be $\sqrt{y} = 9$ .

Now take the left and right sides to the power of 2, so $y = 81$

Now ignore $\sqrt{y}$ and take $\sqrt{x^2}$ in the equation again.

$\sqrt{x^2} = 9$, it applies that $\sqrt{x^2} = x$, then $x = 9$ ,

so

x = 9 ,

y = 81,

x and y are positive integers.