Here's a graph you can play with: https://www.desmos.com/calculator/wy7dptwaij
To start with, both angles are set at 38° so both triangles are congruent (by SAS congruency).
Try changing the slider for b to make that angle bigger and see what happens to the length of YX
And note that the lengths of WX and WZ stay constant.
*edit*
Here is a new graph with calculation for the lengths of ZY and XY and a slider for the length of WY (in the folder):
Let f(x) = x * (3x + 1) = 3x2 + x
Let's see what f(x) is when x is at the endpoints of the interval.
f(-7/3) = 3(-7/3)2 + (-7/3) = 14
f(2) = 3(2)2 + 2 = 14
Aha! they are the same, just as I suspected! 🕵️♀️
Let's see what f(x) is when x is in the interval.
f(0) = 3(0)2 + 0 = 0
And it is true that 0 < 14
Since f(x) is a parabola, we can be sure that f(x) < 14 if and only if x is in the interval (-7/3, 2)
Here's a graph: https://www.desmos.com/calculator/bcaogdbdtx
(This question reminds me of this solution )
m∠EFH = m∠EGF because they are both right angles
m∠FEH = m∠GEF because they are the same angle
So by the AA similarity theorem, △EFH ~ △EGF
EF / EH = EG / EF
Multiply both sides of the equation by EF
EF2 / EH = EG
Multiply both sides of the equation by EH
EF2 = (EG)(EH)
Take the square root of both sides.
EF = \(\sqrt{\text{(EG)(EH)}}\)
By the way, welcome to the forum!
Remember, the radius of a circle is the distance between the center and a point on the circle.
The center of the circle is (2, 3)
The point (-2, 0) is on the circle.
Let's use the distance formula to find the radius.
radius = distance between (2, 3) and (-2, 0)
radius = \(\sqrt{(0-3)^2+(-2-2)^2}\)
radius = \(\sqrt{(-3)^2+(-4)^2}\)
radius = \(\sqrt{9+16}\)
radius = \(\sqrt{25}\)
radius = 5
Here's the graph: https://www.desmos.com/calculator/bewcrh6lwk