What is the correct equation for segment EF?
A. EF¯= (EG2)(GH2)
B. EF¯= (EG)(GH)
C. EF¯= (EG)(EH)
D. EF¯= (EG2)(FG2)
note:EF are line and all the anwser after equal sign are under a square root hope im clear
+9488 (This question reminds me of this solution 
)
m∠EFH = m∠EGF because they are both right angles
m∠FEH = m∠GEF because they are the same angle
So by the AA similarity theorem, △EFH ~ △EGF
EF / EH = EG / EF
Multiply both sides of the equation by EF
EF2 / EH = EG
Multiply both sides of the equation by EH
EF2 = (EG)(EH)
Take the square root of both sides.
EF = √(EG)(EH)
By the way, welcome to the forum!
