Yep, I believe you are correct..... there is a problem with the Q AND my solution had a math error ! D'Oh ! ~ EP
Let's use the correct numbers (thanx , Guest !)
a = arthur now
(a-4) = 11 (j-4) and (a+4) = 4 (j+ 4)
a = 11j -40 11j-40 + 4 = 4j+ 16 shows j = 52/7 then a = 292/7
check: 4 years ago j = 24/7 a = 264/7 CHECK !
check 4 years from now j = 80/7 a = 320/70 CHECK !
Now find when a is twice as old
11j-40 + x = 2 ( j+x)
11(52/7) - 40 + x = 104/7 + 2x
188/7 = x 188/7 years from now a will be twice as old as j CHECK !