Four years ago Arthur is 11 times as old as his son Arthur Jr, but four years from now, Arthur will only be 4 times as old as Jr. What is Arthur’s age when he is twice as old as Arthur Jr?
+37165 a = arthur now
(a-4) = 11 (j-4) and (a+4) = 4 (j+ 4)
a = 11j -40 11j-40 + 4 = 4j+ 16 shows j = 8 then a = 48
now find when he is twice as old as j
a + x = 2 ( j+x)
48 + x = 2(8) + 2x
32 = x 32 years from now arthur = 80 j = 40 y/o
EP: Your 2 equations: (a-4) = 11 (j-4), (a+4) = 4 (j+ 4), solve for a, j give the following fractional results:
a = 292/7 and j = 52/7 [I think there is a mistake in the question] !!
+37165 Yep, I believe you are correct..... there is a problem with the Q AND my solution had a math error ! D'Oh ! 
~ EP
Let's use the correct numbers (thanx , Guest !)
a = arthur now
(a-4) = 11 (j-4) and (a+4) = 4 (j+ 4)
a = 11j -40 11j-40 + 4 = 4j+ 16 shows j = 52/7 then a = 292/7
check: 4 years ago j = 24/7 a = 264/7 CHECK !
check 4 years from now j = 80/7 a = 320/70 CHECK !
Now find when a is twice as old
11j-40 + x = 2 ( j+x)
11(52/7) - 40 + x = 104/7 + 2x
188/7 = x 188/7 years from now a will be twice as old as j CHECK !
