Vinculum

I completely forgot bout the Vieta's formula

I knew I did something wrong when I got those crazy numbers

Thanks, BuilderBoi 

Hey there is something missing in your problem!!!

5+4+87654345+87392+X = what????

-Vinculum

Wait @hipie what happened?

Or you can use "\mathrm{}", for example: $\mathrm{Factor}\:4x^4-12x^3+8x^2+12x-1$

You see how the word "Factor" is in normal font...

You can do that!!!! 

$\prod _{n=3}^5n^{\frac{1}{2\pi }}$

$a_3=3^{\frac{1}{2\pi }}$

$a_4=4^{\frac{1}{2\pi }}$

$a_5=5^{\frac{1}{2\pi }}$

$3^{\frac{1}{2\pi }}\cdot \:4^{\frac{1}{2\pi }}\cdot \:5^{\frac{1}{2\pi }}$

$=60^{\frac{1}{2\pi }}$

Well, I did everything I can, I don't think I can solve this one then. Maybe ask someone or a mod !

-Vinculum

How was it not helpful, what else do you need? 

That's cool I didn't know that!!

Thanks, guest!! Saves a lot of time!!!

Nice one Asinus!!!!

Using the quadratic formula gives:

$_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:7\left(-5\right)}}{2\cdot \:7}$

$x_1=\frac{-1+\sqrt{141}}{2\cdot \:7},\:x_2=\frac{-1-\sqrt{141}}{2\cdot \:7}$

$x=\frac{-1+\sqrt{141}}{14},\:x=\frac{-1-\sqrt{141}}{14}$

So if a and b are roots:

$(\frac{-1+\sqrt{141}}{14}-4)(\frac{-1-\sqrt{141}}{14}-4)$

(EDIT:  Just you are calc if you don't know how to solve!!!)

Just solve that and you got the answer 

-Vinculum