Using the quadratic formula gives:
\(_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:7\left(-5\right)}}{2\cdot \:7}\)
\(x_1=\frac{-1+\sqrt{141}}{2\cdot \:7},\:x_2=\frac{-1-\sqrt{141}}{2\cdot \:7}\)
\(x=\frac{-1+\sqrt{141}}{14},\:x=\frac{-1-\sqrt{141}}{14}\)
So if a and b are roots:
\((\frac{-1+\sqrt{141}}{14}-4)(\frac{-1-\sqrt{141}}{14}-4)\)
(EDIT: Just you are calc if you don't know how to solve!!!)
Just solve that and you got the answer
-Vinculum