\((f\cdot g)(x)=f(x)\cdot g(x)\)
I attest that the notation is funky. It should be relatively simple from here.
\(f(x)=x^3-4x+2\\ g(x)=x^2+2\) | Just multiply them together. |
\((f\cdot g)(x)=(x^3-4x+2)(x^2+2)\) | Now, you are on a mission to find the product of the trinomial and binomial. |
\((f\cdot g)(x)=x^5\textcolor{red}{-4x^3}+2x^2\textcolor{red}{+2x^3}-8x+4\) | Now, combine any existing like terms, which I highlighted for you in red. |
\((f\cdot g)(x)=x^5-2x^3+2x^2-8x+4\) | |
I noticed that you repeated questions, and Omi67 answered your second question here: https://web2.0calc.com/questions/for-the-image-shown-what-is-the-scale-factor
Anyway, I guess I will help you with the third problem.
Notice that all the corresponding angles have the measure and are, therefore, congruent, by the Definition of Congruent Angles. For example, \(m\angle D=m\angle M\) and they are corresponding angles.
If corresponding sides are proportional, then this means that each ratio is equivalent. Pairs of corresponding sides include \(ED, NM\text{ and }DG,MP\text{ and }GF,PO\text{ and }FE,ON\) . The ratio of these sides must be the same in order for both quadrilaterals to be considered similar. Let's check that!
Does \(\frac{ED}{NM}=\frac{DG}{MP}=\frac{GF}{PO}=\frac{FE}{ON}\) ? Well, let's see!
Yes, \(\frac{3}{7.5}=\frac{6}{15}=\frac{12}{30}=\frac{9}{22.5}\) . This means that corresponding sides are proportional. Therefore, yes, \(DEFG\sim MNOP\)
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