http://www.cymath.com/answer.php?q=%20p(x%2Bq)%3Dr
tan=opos.adj.
so let s use pithagorean theorem:
a^2+b^2=c^2
a^2+64=68
a=2
oposite of angle A is a
oposite of angle B is b
oposite of angle C is c (hyp.)
tan=opos.adj.=28
http://www.cymath.com/answer.php?q=0.0155(10)%5E2-1.213(10)%2B75.26
your answer is under the 'Done'
x*20/100=1080
find the x
180-80=100
100/2=50
yes you can :)
csc=hyp.oposite=53cos=adj.hyp.
so we know hyp=5 and oposite=3 let s use pythagorean theorem to find adj :
3^2+x^2=5^2
x=4
so your adj is 4 and hyp is 5
cos=adj.hyp.=45
12000×(1.06)t=29280t−represent year
x+y=12 let s solve for x x=12-y put it in term s of x in the other equation
2x-3y=4 x=12-y
24-2y-3y=4
-5y=-20
y=4
x=12-y y=4
x=12-4
x=8
http://www.cymath.com/answer.php?q=x%2By%3D12%202x-3y%3D4
http://www.cymath.com/answer.php?q=2%2F7*22%201%2F6
16x-10y=10 16x-10y=10 (plus them together)
-8x-6y=6 (x2) -16x-12y=12
-22y=22
y=-1
put y=-1 into one of the equations(i choosed -8x-6y=6 because it is easier):
-8x-6y=6 y=-1
-8x+6=6
-8x=6-6
-8x=0
x=0