Can anyone help me with this one?
Hi Solveit
I let z=x+yi
and this is the graph I got.
I don;t intend to do all the working but I will say that
|z+4+3i|=|(x+4)+(y+3)i|=(x+4)2+(y+3)2etc
see if you can do it from there,
So I came till here, but don't know how to continue:
|x+yi+4+3i|≤|5⋅(x+yi)+10−9i||(x+4)+i⋅(y+3)|≤|(5x+10)+i⋅(5y−9)|√(x+4)2+(y+3)2≤√(5x+10)2+(5y−9)2x2+8x+16+y2+6y+9≤25x2+100x+100+25y2−90y+81x2+8x+y2+6y+25≤25x2+100x+25y2−90y+181−24x2−24y2−92x+96y≤156
Nice work Solviet.
Divide everything by -24
then complete the squares to get (x-h)^2 + (y-k)^2 >= r^2
