Solveit

you can check it by youself put in term s of t  4:

21000(0.9826)^48 = 9042.8174786606693723

21000*0.81^4 = 9039.81141

but i think:

\(V(m)=21,000(0.81)^{\frac{m}{12}} \\ \text{m-represent month}\)

 P(t) = 82,100(1.02)^t

1.t is the time in years 

2.P(t) is the population after t years

3. 100%=1       102-100=2% so the interest rate is 2 %

    102%=1.02

4. after 15 year just put in term s of 't' (wich is represent the years) 15 :

\(82,100 \times(1.02)^{15}=110495.7905764110395150475397398528=110.496\text{ (aprox.)} \)

too much pretend :)

thank you CPhill !

look from here:

Ha Ha very funny

40/60 = 0.6666666666666667

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