hi otterstar!

so we know that \((-2)^4=16\) since -2*-2*-2*-2=16

since there are 4 roots, and we've already covered all the real ones, we have to look for complex numbers now.

we also know that \(i^4=1\), so that means that \((2i)^4=16\) since 2^4 already equals 16, and multiplying it by 1 will equal 16 too.

lastly, we know that \((-2i)^4=16\) since we already know that -2^4 equals 16 (as we found earlier) and multiplying it by i^4=1 will equal 16 too.

so the solutions are \(\boxed{2,-2,2i,-2i}\)

i hope this helped you! :)