Find all complex numbers \(z\) such that \(z^2=2i\).
thank you to anyone who helps! i really appreciate it! :)
The solutions are sqrt(2i) and -sqrt(2i).
yeah that's what i got too, but apparently, it's wrong...
https://web2.0calc.com/questions/find-all-complex-numbers-nbsp-nbsp-such-that-nbsp-nbsp_1
+738 
