KeyLimePi

Thanks for your time

Use pythagorean theorem to find the side of the smaller triangle. 

\(1^2+b^2=5^2\)

\(b=2\sqrt6\)

So continuing with the pythagorean thereom \(2\sqrt{6}^2+5^2=c^2\)

\(c=\sqrt{37}\)

I am assuming the problem asks for a square root version.

Yes I now realize my mistake. If you look in the beginning of my answer you see that I used \(5\) instead of  \(5^2\)

Here is my edited answer...

Use pythagorean theorem to find the side of the smaller triangle. 

\(1^2=b^2=5^2\)

\(1+b^2=25\)

\(b^2=24\)

\(b=\sqrt{24}\)

So continuing with the pythagorean thereom \(\sqrt{24}^2+5^2=c^2\)

\(24+25=c^2\)

\(24+25=49\)

\(\sqrt{49}=7\)

Therefore the answer is \(7\)

Thanks, ElectricPalov and SoulSlayer615 for correcting my previous error,

\(\pi\)

\(36\).

\(6\sqrt2^2\)

Square root of \(2\) squared\(=2\)

\(6^2=36\)

\(36\cdot2\)\(=72 \)

So \(6\sqrt2^2=72\)

Area of triangle\(=(l1\cdot{l2})\div2=a\)

We already calculated the parentheses so now we divide by \(2\)

\(72\div2=36\)

Area of\(\triangle{PQR}=36\)

π

I figured it out :D

yes that works

Its a bit basic

\(5g+6w-g-6w \) 

We can switch \(g\) and \(6w\)

\(5g-g+6w-6w\)

Compute

\(5g-g=4g\) and \(6w-6w=0\)

So \(4g+0\) 

Or just \(4g\)

Yes you are right

-KeyLimePi 

Thanks 

Thanks

Given that the three angles are in the ratio, \(2:3:4\) we can write them as \(2a^\circ\), \(3a^\circ\), and \(4a^\circ\) for some number \(a\).

The sum of the interior angles of any triangle is \(180^\circ\), so we have
\(2a+3a+4a = 180\)
We can write this equation as  \(9a=180\)and solve to get \(a=20\). Thus the measures of the three angles are  \(2\cdot 20=40\) degrees,   \( 3\cdot 20=60\)degrees, and \(4\cdot 20=80\) degrees. In particular, if the largest angle is \(y^\circ\), then \(x=\boxed{80}\).

That's what I got and when I put it in it was correct. 

Edited: Ok I see what you did. You did the exterior angles but the problem asked for the interior angles.