Hi there

Question

+1

766

3

+142

In right triangle PQR, we have angleQ=angleR and PR=6\sqrt(2). What is the area of triangle PQR?

KeyLimePi Mar 24, 2019

imheretosavetheday · Answer 1 · 2019-03-24T04:17:05

+31

0

6sqrt 2 ^2 / 2 = 36, by 45-45-90 triangles

edited by imheretosavetheday Mar 24, 2019
edited by imheretosavetheday Mar 24, 2019

KeyLimePi · Answer 2 · 2019-03-24T04:18:26

+142

+3

yes that works

KeyLimePi Mar 24, 2019

edited by Guest Mar 24, 2019
edited by KeyLimePi Mar 24, 2019
edited by KeyLimePi Apr 14, 2019

KeyLimePi · Answer 3 · 2019-03-24T04:21:10

\(36\).

\(6\sqrt2^2\)

Square root of \(2\) squared\(=2\)

\(6^2=36\)

\(36\cdot2\)\(=72 \)

So \(6\sqrt2^2=72\)

Area of triangle\(=(l1\cdot{l2})\div2=a\)

We already calculated the parentheses so now we divide by \(2\)

\(72\div2=36\)

Area of\(\triangle{PQR}=36\)

π

I figured it out :D