heureka

What is 9/16-1/2

\(\begin{array}{|rcll|} \hline && \frac{9}{16}-\frac{1}{2} \\ &=& \frac{9}{16}-\frac{1}{2} \cdot \frac{8}{8} \\ &=& \frac{9}{16}-\frac{8}{16} \\ &=& \frac{9-8}{16} \\ &=& \frac{1}{16} \\ \hline \end{array} \)

Kevin computes that if x is now the number of shares the client holds in her account, then the number of years y that the client has had the account is given by the function y space equals space square root of x minus 10 end root. what is the domain and range?

\(\begin{array}{|llcll|} \hline & y = \sqrt{x-10} \\\\ \text{Domain} & \{x \in \mathbb{R}:x\ge 10 \} \\ \text{Range} & \{y \in \mathbb{R}:y\ge 0 \} \\ \hline \end{array} \)

What is the formula for surface area of a cone?

The surface area of the cone equals the area of the circle plus the area of the cone and the final formula is given by:

\(\text{Surface Area} = \pi r^2 + \pi rl\)

1324/43 = 30.7906976744

whats the perimeter of a rhombus of height of 4.55 and a base of 5.2

without mistake:

\(\begin{array}{|rcll|} \hline a^2 &=& \left(\dfrac{5.2}{2}\right)^2 +\left(\dfrac{4.55}{2}\right)^2 \\ a &= & \sqrt{2.6^2+2.275^2} \\ &= & \sqrt{6.76+5.175625} \\ &= & \sqrt{11.935625} \\ &= & 3.45479738914 \\\\ \text{Perimeter} &=& 4\cdot a \\ &=& 4\cdot 3.45479738914 \\ &=& 13.8191895566 \\ \hline \end{array}\)

​whats the perimeter of a rhombus of height of 4.55 and a base of 5.2 ?

\(\begin{array}{|rcll|} \hline a^2 &=& \left(\dfrac{5.2}{2}\right)^2 +\left(\dfrac{4.55}{2}\right)^2 \\ &= & \sqrt{2.6^2+2.275^2} \\ &= & \sqrt{6.76+5.175625} \\ &= & \sqrt{11.935625} \\ &= & 3.45479738914 \\\\ \text{Perimeter} &=& 4\cdot a \\ &=& 13.8191895566 \\ \hline \end{array}\)

sqrt(52)

\(\begin{array}{|rcll|} \hline && \sqrt{52} \\ &=& 2\sqrt{13} \\ &=& 7.21110255093 \\ \hline \end{array}\)

COS(X)= -0.75.

Estimate to the nearest hundredths if (X) is greater than or equal to 0* and less than 360*. ((*) = degrees)

\(0 \le x \le 360^{\circ}\)

\(\begin{array}{|rcll|} \hline \cos(x) &=& -0.75 \quad & | \quad \pm \arccos() \\ x &=& \pm \arccos(-0.75) \\ x &=& \pm 138.590377891^\circ \pm k \cdot 360^\circ\\ x_1 &=& 138.590377891^\circ \pm k \cdot 360^\circ \quad & k \in N \quad k= 0,1,2,3,\dots \\ \mathbf{x_1} &\mathbf{=}&\mathbf{ 138.590377891^\circ } \quad & 0 \le x \le 360^{\circ} \\\\ x_2 &=& -138.590377891^\circ \pm k \cdot 360^\circ \quad & k \in N \quad k= 0,1,2,3,\dots \\ x_2 &=& -138.590377891^\circ + 360^\circ \\ \mathbf{x_2} &\mathbf{=}&\mathbf{221.409622109^\circ } \quad & 0 \le x \le 360^{\circ} \\ \hline \end{array} \)