ElectricPavlov

13   + 4 p    =   49  + 3p    solve for p

p = 36

cost will be    13 + 4(36) = $________

 m < 15.87... 

Actually,    m = 15   is the largest integer value of m such that the equation 3x^2 - mx + 21 = 0 has no real solutions.

Ooops !   c = 21

Convert the times to minutes   10  = 600     7 = 420

600 -x = 420 + 5x

x = 30                   600 - 30 = 570   ====>        so     36 minutes ago it was 9:30    making the time now  =  10:06

(x +7+2i)(x+7-2i)     expand and simplify to

x^2 + 14x + 53        <======= take it from here

Please don't just post answers without the method used to reach the solution......it is worthless to do so .

Start by dividing both sides by 2.9

1.9^x / 1.1^x   = 1.9655    Now take the x root of both sides

1.9 / 1.1   = 1.9655^1/x    Now LOG both sides

.237361 = 1/x (.29347)

x = 1.2364

When the ball hits the ground, y=0

0 = -4.9 t^2-3.5t+12.4      Use Quadratic formula to solve for 't'       Throw out the negative value  

'

Discriminant of Quadratic Formula

$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$

b^2 - 4ac  >=0

15^2 - 4(2)(b) >= 0

225 >= 8b

28.125 >= b                 sum = 28 + 27 + 26.......1 = 406    for positive integers

Need more info...