13 + 4 p = 49 + 3p solve for p
p = 36
cost will be 13 + 4(36) = $________
m < 15.87...
Actually, m = 15 is the largest integer value of m such that the equation 3x^2 - mx + 21 = 0 has no real solutions.
Ooops ! c = 21
Convert the times to minutes 10 = 600 7 = 420
600 -x = 420 + 5x
x = 30 600 - 30 = 570 ====> so 36 minutes ago it was 9:30 making the time now = 10:06
(x +7+2i)(x+7-2i) expand and simplify to
x^2 + 14x + 53 <======= take it from here
Please don't just post answers without the method used to reach the solution......it is worthless to do so .
Start by dividing both sides by 2.9
1.9x / 1.1x = 1.9655 Now take the x root of both sides
1.9 / 1.1 = 1.96551/x Now LOG both sides
.237361 = 1/x (.29347)
x = 1.2364
When the ball hits the ground, y=0
0 = -4.9 t^2-3.5t+12.4 Use Quadratic formula to solve for 't' Throw out the negative value
'
Discriminant of Quadratic Formula
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
b^2 - 4ac >=0
15^2 - 4(2)(b) >= 0
225 >= 8b
28.125 >= b sum = 28 + 27 + 26.......1 = 406 for positive integers
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