Dome shaped parabola max occurs at t = - b/ 2a = - 18/(2*(-1)) = t = 9
sub in t = 9 into the equation to find the max value of the expression ......
This is a bowl shaped parabola ( the coefficient of t^2 is positive)
mine occurs at t = - b/2a = - - 8 /2 = 4
xy = 24
x^2 + y^2 = 73
now: ( x-y)^2 = ( x^2 + y^2 ) - 2xy sub in the values above
= 73 - 2(24) = 25
Wellll..... xy = B (2)(8) = B = 16
then A (22) + 16 = 8 solve for 'A'
Yep, I sure did ! I seem to miss those tiny ' - ' signs pretty regularly
Thanx for checking my math, BuilderBoi !
Three.
(3x+5/6 x )^2 = 9x^2 + 5x + 25/36
Slope is defined as rise/run if run = 0 (as a vertical line) then the slope is UNDEFINED .(zero in the denominator)
5 cm * 5 cm * 5 cm = 125 cm3
Note the vertex at 3, 8
vertex form y = a(x-3)^2 + 8 sub in a point to solve for 'a' I'll use 5,4
4 = a ( 5-3)^2 + 8
a = -1
y = -(x-3)^2 + 8 expand to y = -x^2 + 6x -1 <======== take it from here !