16 + 8 - 5 = 19
-12 thru -1 cancel out the 1 thru 12 then there is only 13 left
total = 13
4(x + 7)(2 - x) + 2x^2 + 8x - 3 simplify to
-4x^2 -20x +56 + 2x^2 + 8x-3
-2x^2 -12x + 53 max will occur at x = -b/2a = - -12/((2)(-2) = - 3
use this 'x' in the equation to calculate the max value (the 'y' value)
Slope, m = 3/-3 = -1
y = -x + b
11 = -1+ b b = 12
y = - x + 12
x+y = 12
x/12 + y/12 = 1 < ======== a = 12
12 x 250 m^2 * 1 ft / .3048 m * 1 ft / .3048 m * 1 gal / 200 ft2 = 161.45 gal = ~~ 162 gallons needed
6 (y^2 - 1/6 y - 15/6)
6 ( y - 1 2/3) (y +1 1/2 ) <========= you can finish
GCM of 12 and 18 is six bags of 2 peanut and 3 oatmeal
2x(x + 10) = -50 expand and simplify to
2x^2 + 20x + 50 = 0 or
x^2 + 10x + 25 =0
(x+5)(x+5) = 0 shows only one root x = - 5 (a 'double root')
sum = -5
g(x) will have to be degree 6 for h(x) to have a degree 6 term since f(x) is only degree 4
From Vieta
r1r2 =29/2
r1+r2 = - -3/2 = 3/2
( r1+r2)^2 = (3/2 )2 = r1^2 + r2^2 + 2r1r2
= 9/4 = r1^2 + r2^2 + 2(29/2)
r1^2 + r2^2 = 9/4 - 29 = -107/4
