Not sure what you need...maybe this
3g+2 = x
3g = x-2
g = (x-2) / 3
c = original amount of chocs
3/4 c = dark 1/4 c = w
(1/4 c ) 1/2 = 3/4 c - 90 c = 144
(3 ÷ 8) x 100% = 37.5 %
x = origianl amount
x - 1/5x + 5 after d = 4/5 x + 5 remaining
(4/5x+5) - (2/3 ( 4/5 x + 5) +3 ) = 4/15 x - 4/3 remaining after A
then Ben takes 1/4 leaving 3/4 3/4 (4/15 x - 4/3) = 21
x = originally 110
10c5 10c6 10c7 10c8 10c9 10c10
252 + 210 + 120 + 45 + 10 + 1 = ( I think !)
29/289*z < 16/161*z - 16
subtract 16/161 z from both sides
then you'll divide by the coefficient of z
45/ 46259 z < - 16
z < -16 (46259/45)
(x-1-sqrt2)(x-1+sqrt2)(x-2-sqrt2)(x-2+sqrt2) =
x^4- 6x^3+ 9x^2-2 after all of the multiplication ( I used an online calculator)
Seems I made that more difficult than necessary.....
rotate the vector 90 degree counter clockwise
cos 90 - sin 90
sin 90 cos 90 or : 0 -1
1 0
-8r<-12 + 2r. subtract 2 r from both sides
-10r < -12 divide both sides by -10 ....note: this flips the < to >
r> 12/10
r > 6/5
120 = -6t^2 + 51 t
-6t^2 + 51 t -120 = 0 Quadratic formula show t = imaginary numbers ..... no answer ...as asinus found !
