The equation y = -6t^2 + 51t describes the height (in feet) of a projectile launched from the surface of Mars at 51 feet per second. In how many seconds will the projectile first reach 120 feet in height?
+15069 In how many seconds will the projectile first reach 120 feet in height?
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f(t)=−6t2+51tdf(t)dt=−12t+51=0t=4.25
hmax=−6⋅4.252+51⋅4.25
hmax=108.375 feet
The projectile cannot reach a height of 120 feet.
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+37167 120 = -6t^2 + 51 t
-6t^2 + 51 t -120 = 0 Quadratic formula show t = imaginary numbers ..... no answer ...as asinus found !
